Parametry Gęstość prawdopodobieństwa Dystrybuanta ${\displaystyle a:~a\in (-\infty ,\infty )}$${\displaystyle b:~b>a}$${\displaystyle c:~a\leqslant c\leqslant b}$ ${\displaystyle a\leqslant x\leqslant b}$ ${\displaystyle \left\{{\begin{matrix}{\frac {2(x-a)}{(b-a)(c-a)}}&\mathrm {dla\ } a\leqslant x\leqslant c\\&\\{\frac {2(b-x)}{(b-a)(b-c)}}&\mathrm {dla\ } c\leqslant x\leqslant b\end{matrix}}\right.}$ ${\displaystyle \left\{{\begin{matrix}{\frac {(x-a)^{2}}{(b-a)(c-a)}}&\mathrm {dla\ } a\leqslant x\leqslant c\\&\\1-{\frac {(b-x)^{2}}{(b-a)(b-c)}}&\mathrm {dla\ } c\leqslant x\leqslant b\end{matrix}}\right.}$ ${\displaystyle {\frac {a+b+c}{3}}}$ ${\displaystyle \left\{{\begin{matrix}a+{\frac {\sqrt {(b-a)(c-a)}}{\sqrt {2}}}&\mathrm {dla\ } c\!\geqslant \!{\frac {b\!-\!a}{2}}\\&\\b-{\frac {\sqrt {(b-a)(b-c)}}{\sqrt {2}}}&\mathrm {dla\ } c\!\leqslant \!{\frac {b\!-\!a}{2}}\end{matrix}}\right.}$ ${\displaystyle c}$ ${\displaystyle {\tfrac {a^{2}+b^{2}+c^{2}-ab-ac-bc}{18}}}$ ${\displaystyle {\tfrac {{\sqrt {2}}(a\!+\!b\!-\!2c)(2a\!-\!b\!-\!c)(a\!-\!2b\!+\!c)}{5(a^{2}\!+\!b^{2}\!+\!c^{2}\!-\!ab\!-\!ac\!-\!bc)^{\frac {3}{2}}}}}$ ${\displaystyle -{\frac {3}{5}}}$ ${\displaystyle {\frac {1}{2}}+\ln \left({\frac {b-a}{2}}\right)}$ ${\displaystyle 2{\tfrac {(b\!-\!c)e^{at}\!-\!(b\!-\!a)e^{ct}\!+\!(c\!-\!a)e^{bt}}{(b-a)(c-a)(b-c)t^{2}}}}$ ${\displaystyle -2{\tfrac {(b\!-\!c)e^{iat}\!-\!(b\!-\!a)e^{ict}\!+\!(c\!-\!a)e^{ibt}}{(b-a)(c-a)(b-c)t^{2}}}}$
${\displaystyle f(x)=\left\{{\begin{array}{cll}0&{\text{dla}}&x<\mu -{\sqrt {6}}\sigma \\{\frac {x-\mu }{6\sigma ^{2}}}+{\frac {1}{{\sqrt {6}}\sigma }}&{\text{dla}}&\mu -{\sqrt {6}}\sigma \leqslant x\leqslant \mu \\-{\frac {x-\mu }{6\sigma ^{2}}}+{\frac {1}{{\sqrt {6}}\sigma }}&{\text{dla}}&\mu \leqslant x\leqslant \mu +{\sqrt {6}}\sigma \\0&{\text{dla}}&x>\mu +{\sqrt {6}}\sigma \end{array}}\right.,}$
${\displaystyle \sigma }$odchylenie standardowe,
${\displaystyle \mu }$wartość średnia.